delayedfriday delayedfriday
  • 02-03-2016
  • Mathematics
contestada

Solve each system using substitution:
2x+2y=38
y=x+3

Respuesta :

hworonie hworonie
  • 02-03-2016
2x+2(x+3)=38
2x+2x+6=38
4x+6=38
4x=32
x=8

y=8+3
y=11
Answer Link
Exvited
Exvited Exvited
  • 02-03-2016
[tex]2x+2y=38 \\ y = x + 3 \\ \\ \\ 2x+ 2 (x + 3) = 38 \\ \\ 2x + 2(x + 3) \\ \\ 2x + 2x + 6 \\ \\ 4x + 6 \\ \\ 4x + 6 = 38 \\ \\ 4x + 6 - 6 = 38 - 6 \\ \\ 4x = 32 \\ \\ \frac{4x}{4} = \frac{32}{4} \\ \\ x = 8 \\ \\ y = 11 \\ \\ [/tex]

The final result is: x = 8 and y = 11.
Answer Link

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