Given:
u(initial velocity): 0
a(acceleration): 0.13 m/sâ§2
distance = 458 m
Now  s= ut +1/2 (atâ§2)
Substituting from the given values we get
458= 0+ 1/2(0.13 x tâ§2)
t = 83.94 secs
Now v (velocity)= u+ at
Substituting for t as 83.94 secs and for a and u from the given values we get:
v= 0+0.13 x t
v= 0.13 Ă 83.94
v=10.91 m/s
Therefore the final velocity of the boat is 10.91 m/s and the time taken for the boat to travel 458 m is 83.94 secs