Answer:
1. 7.0 u; 2. 81 u; 3. 12.7 h.
Step-by-step explanation:
Grahamâs Law applies to the diffusion of gases:
The rate of diffusion (r) of a gas is inversely proportional to the square root of its molar mass (M).
r = 1/âM
If you have two gases, the ratio of their rates of diffusion is
râ/râ = â(Mâ/Mâ)
1. Molecular mass
râ/râ = (2.5râ)/râ = 2.5
2.5 = â(44.01/Mâ)
Square both sides: Â Â Â Â Â Â Â Â Â Â 6.25 = 44.01/Mâ
Multiply each side by Mâ: Â Â Â 6.25Mâ = 44.01
Divide each side by 6.25: Â Â Â Â Â Â Mâ = 7.0 u
The molecular mass of the gas is 7.0 u.
2. Â Molecular mass
râ/râ = (râ/1.7)/râ = 1/1.7
1/1.7 = â(28.01/Mâ)
Square both sides: Â Â Â Â Â Â Â Â Â Â Â 1/2.89 = 28.01/Mâ
Multiply each side by Mâ: Â Â Â Â Mâ/2.89 = 28.01
Multiply each side by 2.89: Â Â Â Â Â Â Mâ = 81 u
The molecular mass of the gas is 81 u.
3. Time for diffusion
The time for effusion is inversely proportional to the rate. The faster the rate, the slower the time. Thus,
tâ/tâ = â(Mâ/Mâ)
Multiply each side by tâ
tâ = tââ(Mâ/Mâ) = 4.5â(16.04/2.016) = 4.5â7.956 = 4.5 Ă 2.82 = 12.7 h
It would take methane 12.7 h to diffuse.