Answer:
0.2
Explanation:
The given parameters are;
The acceleration of the train, a = 0.2¡g
The mass of the person standing on the train = m
Let Îź represent the coefficient of static friction, we have;
The force acting on the person, F = m à a = m à 0.2¡g
The force of friction acting between the feet and the floor, [tex]F_f[/tex] = m¡g¡Ο
For the person not to slide we have;
The force acting on the person = The force of friction acting between the feet and the floor
F = [tex]F_f[/tex]
ⴠm à 0.2¡g = m¡g¡Ο
From which we get;
0.2 = Îź
The coefficient of static friction that must exist between the feet and the floor if the person is not to slide, Îź = 0.2.