The diameter of a basketball rim is 18 inches. A standard basketball has a circumference of 30 inches. What is the distance between the ball and the rim in a shot in which the ball goes exactly in the center of the rim? Show your work.

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02-05-2018
Mathematics

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The diameter of a basketball rim is 18 inches. A standard basketball has a circumference of 30 inches. What is the distance between the ball and the rim in a shot in which the ball goes exactly in the center of the rim? Show your work.

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calculista calculista · Answer 1 · 2018-05-11T21:49:40+02:00

we know that
circumference=2*pi*r-------> r=circumference/(2*pi)
circumference=30 in
r=circumference/(2*pi)------> 30/(2*pi)-----> 4.7746 in
the radius of a standard basketball is 4.77 in

the distance between the ball and the rim is equal to
radius of a basketball rim minus radius of a a standard basketball
radius of a basketball rim =18/2------> 9 in
radius of a a standard basketball=4.77 in

the distance between the ball and the rim=[9-4.77]------> 4.23 in

the answer is
4.23 in

carlosego carlosego · Answer 2 · 2018-05-11T21:57:04+02:00

To solve this problem you must apply the proccedure shown below:

1. You have the following information given in the problem above:

- The diameter of a basketball rim is 18 inches.
- A standard basketball has a circumference of 30 inches.

2. Therefore, the diameter of the standard basketball is:

D=30 inches/π
D=9.54 inches

3. Therefore you have:

(18 inches-9.54 inches)=8.45 inches on both sides

4. Then, the distance the distance between the ball and the rim in a shot in which the ball goes exactly in the center of the rim, is:

d=8.45 inches/2
d=4.22 inches

The answer is: 4.22 inches