Jane and Anne are at a garage sale, and they are both buying clocks for their collections. When they leave, Jane has twice as many clocks as Anne does. then Jane picks up 4 more at another sale on the way home. So she has 10 all together. How many clocks did Anne buy?

Respuesta :

She has three...

10 - 4 = 6
Half of 6 is 3


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Solution:

Let number of clocks does Anne possess when she and Jane leave shop

Β  Β  Β  Β  Β = p clocks

Number of Clocks possessed by Jane when she and Anne left shop

Β  Β  Β  Β  Β  Β = Β 2 p clocks

Number of clocks bought by Jane while travelling from garage to home

Β  Β  Β  Β  = 4 clocks

Total Clocks does Jane possess currently = 10

β†’β†’β†’Expressing the above statement in equation form

β†’2 p + 4 = 10

β†’ 2 p = 10 - 4 Β [Bringing variable on Right side of equation]

β†’2 p = 6

β†’p = 3 Β  Β  β‡’ [Dividing both side by 2]

Number of clocks bought by Anne when she was in garage = 3 clocks